Question

A ship leaves on a long voyage. When it is 18 miles from the shore, a seaplane, whose speed is ten times that of the ship is sent to deliver mail. How far from the shore does the seaplane catch up with the ship?

Answer 1

Hi there !
Here's the answer:

•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•

Let the speed of Ship be x miles/hr
Then speed of sea plane = 10x miles/hr

Let the time taken by ship to travel 18 miles be t

•°• Speed of ship $x = \frac{18}{t}$
Speed of the sea plane = $= \frac{180}{t}$

Distance travelled by ship during next t' time = $18 + \frac{18×t'}{t}$

• Distance travelled by Seaplane = $\frac{180×t'}{t}$

Equate both

$18 + \frac{18×t'}{t} = \frac{180×t'}{t}$

$\frac{162×t'}{t} = 18$

=> $\frac{t'}{t} = \frac{18}{162}$

•°• Distance to be covered by the seaplane from the shore to catch up the ship = $180 × \frac{18}{162} = 20$ miles

•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•