Question

A ship leaves the island of Guam and sails
285 km at 40° north of west. In which
direction must it now head and how far must
it sail so that tills resultant displacement
will be 115 km directly of east It Guan.​

Answer 1

Explanation:

i hope it will be helpful

Answer 2

Answer:

The ship must travel kilometers $380$at a 29-degree south-east angle.

Explanation:

Let G be Guam, A be the starting place, and B be the final destination

Let we have 3 vectors:  $\bar u$$=$ $\bar AG$,  $\bar v$$=$$\bar AB$  and  $\bar w$$=$ $\bar GB$.

Then we have the following vector equation:

   $\bar u$$+$  $\bar v$ $=$ $\bar w$

Let $\bar V$$= (x, y).$

Then for projections we have the following 2 equations:

For x: −$285$ * cos 40° + $x= 115.$

For y: $285$ * sin 40° + $y = 0$.

Solving these equations we get:

= 115 + 285 * cos 40° ≈ 333

= −285 * sin 40° ≈ −183

Let’s find the distance and the angle:

$|\bar V|$ = $\sqrt{2 + 2}$ = $\sqrt{3332 + 1832}$ = $\sqrt{110889 + 33489}$ ≈ $380km.$

                           

Angle: =$atan$ |$\frac{v}{x}$ |= $atan$ |− $\frac{133}{ 333}$| ≈29° .

To learn more about displacement, Visit:

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