Question

a ship moves along the equator to the east with velocity v0=30km/h. the southeastern wind blows at an angle theta 60 degree to the equator with velocity v=15km/h. find the wind velocity v' relative to the ship and the angle theta between the equator and the wind direction in the reference frame fixed to the ship .... I.E.IRODOV ..ch. 1 kinematics..Q. 1.6​

Answer 1

Answer:

We have

v

′

=

v

−

v

0

(1)

From the vector diagram [of equation (1)] and using properties of triangle

v

′

=

v

0

2

+v

2

+2v

0

vcosφ

=39.7km/h (2)

and

sin(π−φ)

v

′

=

sinθ

v

or, sinθ=

v

′

vsinφ

or θ=sin

−1

(

v

′

vvsin

)

Using (2) and putting the values of v and d

θ=19.1 °

Explanation:

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