Question

A ship moving at a speed of 56 km per hour 1 second later it is moving at 58 km per hour what is its acceleration

Answer 1

Answer:

0.6 m/s^2

Explanation:

According to the given question,

u = initial velocity = 56 km/h = 56×1000/3600 = 15.5 m/s

v = final velocity = 58 km/h = 16.1 m/s

t = time = 1 sec

a = acceleration

And we are asked to find the acceleration of the ship.

We know,

• v = u+ at

Putting the values we get,

• 16.1 = 15.5 + a×1

• a = 16.1 - 15.5

• a = 0.6 m/s^2

Thus acceleration of the ship is 0.6 m/s^2.

Answer 2

Answer:-

Initial velocity=IV

FV =Finial velocity

A=Acceleration

$V = IV = 56 km/h \\ </p><p>= 56× \frac{1000}{3600} \\ </p><p>= 15.5 m/s$

V = FV= 58 km/h

= 16.1 m/s

T= time = 1 sec

V= u+ at

Adding the values we have,

$16.1 = 15.5 + a×1 \\ </p><p>a = 16.1 - 15.5 \\ </p><p>a = 0.6 m/s^2$

Acceleration

$=0.6 m/s^2$