Question

A ship moving with a constant acceleration of 36 km/h in a fixed direction speeds up from 18 km/h to 36km/h. Find the distance travelled by the ship in this period.​

Answer 1

Given,

a = 36 km/h

u = 18 km/h

v = 36 km/h

Using the velocity-position relation

$v^{2}-u^{2} =2as\\36^{2}-18^{2} =2*36*s\\\\1296-324= 72s\\\\s = \frac{972}{72}$

s = 13.5 km

Hence, the distance travelled by the ship during this period is 13.5km