Question

A ship moving with a constant acceleration of 36 km/h in a fixed direction speeds up from 18 km/h to 36km/h. Find the distance travelled by the ship in this period.​

Answer 1

Explanation:

$we \: will \: use \: equation \: of \: motion$

$v {}^{2} - u {}^{2} = 2as$

$here \\ \\ v = 36 km/h$

$u = 18 km/h$

$a = 36 \: km/h²$

$therefore \\ \\ 36 {}^{2} - 18 {}^{2} = 2 \times 36 \times s \\ s = 972 \div 72 = 13.5 \: km$

$please \: mark \: brainliest$