. A ship moving with a constant acceleration of 36 km/h2
in a fixed direction speeds up
from 12 km/h to 18 km/h .Find the distance traversed by the ship in this period.
Answers
Answered by
8
v^2=u^2+2as
18^2=12^2 + 2 × 36 × s
324-144=72s
180/72=s
s=2.5 km
distance travelled is 2.5 km
18^2=12^2 + 2 × 36 × s
324-144=72s
180/72=s
s=2.5 km
distance travelled is 2.5 km
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Answered by
3
v^2=u^2+2as
18^2=12^2 + 2 × 36 × s
324-144=72s
180/72=s
s=2.5 km
distance travelled is 2.5 km
Hope it will work
18^2=12^2 + 2 × 36 × s
324-144=72s
180/72=s
s=2.5 km
distance travelled is 2.5 km
Hope it will work
thanks
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