a ship moving with a constant acceleration of 36 km per hour square In fixed directions speed of from 12 km per hour to 18 km per hour find the distance travelled by the Sheep in this period
Answers
Answered by
13
u= 12
v- 18
a= 36
v=u+ at
18= 12+ 36*t
6/36=t
t= 1/6
s=ut+1/2 at square
12*1/6+ 1/2 36* 1/6 square
= 2.50 hours
v- 18
a= 36
v=u+ at
18= 12+ 36*t
6/36=t
t= 1/6
s=ut+1/2 at square
12*1/6+ 1/2 36* 1/6 square
= 2.50 hours
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Answered by
3
u=12
a=36
v=18
v=u+at
18=12+36×t
6/36=t
t=1/6
s = ut+1/2at square
12*1/6+1/2 36*1/6 square
=2.50 hours
a=36
v=18
v=u+at
18=12+36×t
6/36=t
t=1/6
s = ut+1/2at square
12*1/6+1/2 36*1/6 square
=2.50 hours
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