Question

A ship moving with a constant acceleration of 36km/h² in a fixed direction speed up from 12km/h to 18km/h . Find the distance traverse by the ship in this period.

Answer 1

u= 12v- 18
a= 36v=u+ at
18= 12+ 36*t
6/36=t
t= 1/6
s=ut+1/2 at square
12*1/6+ 1/2 36* 1/6 square
= 2.50 hours .