Question

a ship moving with a constant acceleration of 36km/h² in a fixed direction speeds up from 12km to 18km .find the distance traversed by the ship in this period

Answer 1

Answer:  2.5

Explanation:

Initial speed=12km/hr (u)

final speed= 18km/hr (v)

constant accleration = 36km/hr(a)

we know that

v² = u² + 2as

s = distance

⇒s= v²-u²÷ 2a

s=18²-12²÷2×36

s= 324-144÷72

s=180÷72=10÷4 [divide both by 18]

s=2.5km