Question

A ship of mass 3×10^7 kg initially at rest is pulled by a force of 5×10^4 N through a distance due to water is negligible. Determine the speed of the ship.​

Answer 1

Answer:

we need to find speed of ship

so acceleration of ship will be

a=f/m

a=5×10^4/3×10^7

=1.666667 ×10^-3=0.00166667 m/s^2

to find speed

v^2-u^2=2as

u=0 s= negligible

v^2=2a

v=0.0577 m/s

answer v is 0.0577 m/s

vinay