Question

A ship of mass 3 × 10^7 kg initially at rest is pulled by a force of 5× 10^4 newton through a distance of 3 cm that the resistance due to water is negligible the speed of the ship is? ​

Answer 1

SOLUTION

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Given that:-

mass(m)= 3×10^7 kg

force (f)= 5×10^4N

Distance (s)=3cm

u=0

We have to find out the velocity...

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Here , using newton 2nd law of motion...

Here , using newton 2nd law of motion...F=ma

=>a = F/m

=>a = 5/3×10^-3

we get acceleration value

we get acceleration valuewe know that....

${v}^{2} = {u}^{2} + 2as$

putting the value of u ,a and s

we get,

v^2 = 0^2+2×5/3×10^-3×3

=> v^2 = 0^2+2×5/3×10^-3×3=>v^2=0+10×10^-3

=> v^2 = 10^-2

=> v= 1/10=0.1

Hence the speed of the ship is 0.1 m/s

Hope it will help you ✌️

Answer 2

Answer:

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