A ship of mass 3×10^7 kg initially at rest is pulled by a Force of 5×10^4 N through a distance of 3 m.Neglecting friction, the speed of ship at this moment is?
Answers
Answered by
25
force = mass × acc.
5×10^4=3×10^7×a
a=5×10^4/3×10^7
1/600=a
now ,v^2-u^2=2as
u =0 due to in rest
v=root(2as)
v=root(2×1/600×3)
v=1/10m/s
v=0.1m/s
5×10^4=3×10^7×a
a=5×10^4/3×10^7
1/600=a
now ,v^2-u^2=2as
u =0 due to in rest
v=root(2as)
v=root(2×1/600×3)
v=1/10m/s
v=0.1m/s
Similar questions
Math,
8 months ago
English,
8 months ago
India Languages,
8 months ago
Math,
1 year ago
Science,
1 year ago