a ship of mass 3 *10 power of 7 kg initially at rest is pulled by a force of 5 * 10 to power 4 newton to throw a distance of 3 minutes asuming that the resistance due to water is negligible the speed of the ship is with full answer in note book and send to me please
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we know that F=ma,
and a=v/t, so F=mv/t by this formula,
v=Ft/m=5x10^4x180/3x10^7=0.3m/s
and a=v/t, so F=mv/t by this formula,
v=Ft/m=5x10^4x180/3x10^7=0.3m/s
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