a ship of mass 3 into 10 power 7 kg initially at rest is pulled by a force 3 into 10 power 4 N through distance of 20 m s during the resistance due to water to win negligible what is the speed of ship
Answers
correct question: A ship of mass 3 * 10⁷ kg initially at rest is pulled by a force 3 * 10⁴ N through distance of 20 m. Assuming that the resistance due to water is negligible, the speed of the ship is
Solution : a/c to question;
- Mass of ship, m = 3 * 10⁷ kg
- Force, F = 3 * 10⁴ N
- displacement, s = 20 m
Now, we use formula of force;
⟹ force = mass * acceleration
⟹ acceleration = force/mass
⟹ acceleration = 3 * 10⁴/3 * 10⁷
⟹ acceleration = 10^( - 3 ) m/s²
We know that, initial velocity, u is 0.
Now, we use kinematical equation
⟹ v² = u² + 2as
⟹ v² - u² = 2as
⟹ v² - 0 = 2 * 10^( - 3 ) * 20
⟹ v² = 40 * 10^( - 3 )
⟹ v² = 40 * 10^( - 3 )
⟹ v = √0.04
⟹ v = 0.2 m/s
Answer : Hence, the speed of ship is 0.2 m/s
More info :
⟹ 0.2 m/s = 0.2 * 1/1000/1/3600
= 0.2 * 3600/1000 = 0.2 * 3.6 = 0.72 km/hr
{The speed of ship is 0.72 km/hr}
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