Question

A ship of mass 3x10^7 Kg initially at rest is pulled
by a force of 5x10^4 N through a distance of 3m.
Assume that the resistance due to water is negligible, the speed of the ship is​

Answer 1

Answer:

0.1m/s

Explanation:

F=ma

Thus a = (5/3)*10^-3

v^2 = u^2 + 2as

Here u is 0 as the ship was initially at rest.

Thus v^2 = 2*(5/3)*10^-3.

Once you solve this very simple calculation you will get v = 10^-1 m/s = 0.1m/s