Question

A ship sails 60km due north then 20km due west and finally 39km south.how far it is from it's starting point?​

Answer 1

Answer:

29 km to the North-West

Step-by-step explanation:

Let us assume the ship starts from point A, reaches point B and then C and the final position is point D.

ADE is a right angled triangle.

DE = BC = 20 km

BE = CD = 39 km

AE = AB - EB = 60 - 39 = 21 km

Using Pythagoras theorem,

AD² = DE² + AE²

⇒ AD² = 20² + 21²

⇒ AD² = 400 + 441

⇒ AD² = 841

⇒ AD =  29 km

So, the ship is 29 km to the North-West of the starting point.