Question

A ship sails due east 30 and then due south for 16 km. how far, in a direct line, is it from the starting point? ​

Answer 1

Answer:

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Answer 2

Ship is at 34 km apart from the starting point.

Step-by-step explanation:

A ship sails 30 km due East then sials 10 km South.

In the figure attached,

Ship was initially at O, then moved 30 km to the point B and 16 km to the south.

We have to find the distance AC

By Pythagoras theorem in triangle ABC,

AC = $\sqrt{30^{2}+16^{2}}$

AC = $\sqrt{900+256}$

     = $\sqrt{1156}$

     = 34 km

Therefore, ship is at 34 km apart from the starting point.

Learn more about the Pythagoras theorem from https://brainly.in/question/11669487