A ship sends an ultrasound that returns from the sea bed and is detected after 3.42 s. If the speed of the ultrasound through sea water is 1531 m/s, what is the distance of the sea bed from the ship ?
Answers
Answered by
0
The total distance covered by U.S is 2 times distance of seabed from the ship{2D}.
S=Vt
2D=Vt
D=Vt/2
D==>>>>>>>>>>>>>
S=Vt
2D=Vt
D=Vt/2
D==>>>>>>>>>>>>>
Hujaifa1:
Thanks
Answered by
0
Hello!!
As speed =Distance/Time
Distance=Speed X Time
So Distance=1531 X 3.42
Distance =5236.02 m/s
And Distance in Kilometre/hour= 18/5 X 5236.02
=18849.672 km/hr
Hope It will Help You!!
As speed =Distance/Time
Distance=Speed X Time
So Distance=1531 X 3.42
Distance =5236.02 m/s
And Distance in Kilometre/hour= 18/5 X 5236.02
=18849.672 km/hr
Hope It will Help You!!
Similar questions