Question

a ship sends out ultrasound that returns from the sea bed and is detected after 3.42 s. if the speed of ultrasound is 1531m/s, what is the distance of seabed from the ship?

Answer 1

Distance ( d ) = ?

Time ( t ) = 3.42 s

Velocity ( V ) = 1531m/s

d = Vt / 2

d = 1531 × 3.42 / 2

d = 2618•01 m

Answer 2

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A ship sends out ultrasound that returns from the sea bed and is detected after 3.42 s. if the speed of ultrasound is 1531m/s, what is the distance of seabed from the ship?

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➦Given : -

• Time taken(t) = 3.42 sec.
• Speed of ultrasound(v) = 1531 m/s

➦To Find : -

• Distance(d) travelled by the ultrasound = ?

➙Distance travelled by the ultrasound : -

⇒2 × depth of sea = 2d

➦On Substituting Values : -

⇒2d = speed of sound × time

⇒2d = 1531 m/s × 3.42 sec.

⇒d = 5236m/2

⇒d = 2618 m.

➙Thus , the Distance of the seabed from ship is 2618m ...