Question

A Ship Sends Out Ultrasound That Returns From The Seabed And Is Detected After 3.42 Second . If The Speed Of Ultra Sound Through Sea Water Is 1531 M/S ,What Is The Distance Of The Seabed From The Ship

Answer 1

Answer:

$2618.01 \ m$

Explanation:

The ultrasound rays take 3.42 seconds to return to the ship. Means, they take 1.71 seconds to reach the seabed.

The velocity is 1531 m/s.

Hence, the distance is,

$d = vt = 1531 \times 1.71 = 2618.01 \ m$

Answer 2

Answer:

Echo travels twice the distance d (to an fro) before detection = 2d

v = 1531m/s

time of detection = 2d/v

d = (t*v)/2

d = (3.42*1531)/2 = 2618 m

The Distance Of The Seabed From The Ship = 2618m