Question

A ship sends out ultrasound that returns from the seabed and is detected after 3.42s. If the speed of ultrasound through seawater is 1531m/s. What is the distance of the seabed from the ship?​

Answer 1

$\huge\star\underline\mathtt\purple{Answer:-}$

Given:-

t = 3.42s

v = 1531m/s

_________________________

Distance travelled by the ultrasound

= 2× depth of the sea

= 2d

_________________________

where d is the depth of the sea

2d = speed of sound × time

= 1531m/s × 3.42s

= 5236m

d = $\frac{5236}{2}$

= 2618m

Answer 2

Distance of sea bed from ship = Speed of sound * time taken / 2

Distance of sea bed from ship = Speed of sound * time taken / 2= 1531 * 3.42 / 2 = 2618 m