Question

A ship Sends ultrasound that return from the Sea bed and detected after 2.8 seconds if the speed of ultrasound the seawater 1531 M per second what is the depth of the sea

Answer 1

t=2.8s
v=1531m/s
Depth of the sea=
2d=v×t
d=v×t÷2
d=1531×2.8÷2
d=4286.8÷2
d=21434m