Question

A ship sense of sound signal to the seabed and receives the echo after five seconds if the depth of the sea at the place is 3750 m find the speed of the sound in the sea water

Answer 1

Answer:

Given:

Ship receives echo from ocean bed after 5 seconds. Depth at that point is 3750 m

To find:

Speed of sound in water

Concept:

Sound waves released from under-surface of ships travel down and reach ocean bed. From there, they undergo reflection and come upwards and analysed by the ship.

Hence the wave actually travels twice the depth of ocean bed.

Calculation:

Let speed of sound in water be v.

$\sf{ \therefore \: 2d = v \times t}$

$\sf{ = > 2 \times 3750 = v \times 5}$

$\sf{ = > v = \dfrac{2 \times 3750}{5}}$

$\sf{ = > v = 2 \times 750}$

$\sf{ = > v = 1500 \: m {s}^{ - 1}}$

So final answer is:

$\boxed{ \sf{ \bold{ \red{ \huge{v = 1500 \: m {s}^{ - 1}}}}}}$

Additional information:

• This method is used in SONAR to detect depth of sea bed.
• This is used to detect enemy submarines and it's depth.
• It helps to locate colony of fishes in a particular region of the sea.

Answer 2

$\blue{\underline{ \huge{ \blue{\boxed{ \mathfrak{\fcolorbox{red}{orange}{\purple{Answer}}}}}}}} \\ \\ \star \: \boxed{ \rm{ \huge{\red{S} \blue{O} \pink{N} \purple{A} \orange{R}}}} \\ \\ \star \rm \: \red{Given} \\ \\ \leadsto \rm \: deapth \: of \: sea = 3750 \: m \\ \\ \leadsto \rm \: time \: to \: receive \: an \: echo = 5 \: s \\ \\ \star \rm \: \red{To \: Find} \\ \\ \leadsto \rm \: speed \: of \: sound \: in \: the \: sea \: water... \\ \\ \star \rm \: \red{Concept} \\ \\ \leadsto \rm \: let \: depth \: of \: sea \: is \: d \: then \: we \: can \\ \rm \: say \: that \: the \: total \: distance \: travelled \\ \rm \: by \: sound \: signal\: in \: water \: is \: 2d \\ \\ \star \rm \: \red{Formula} \\ \\ \leadsto \rm \: formula \: of \: speed \: is \: giveb \: by... \\ \\ \: \: \: \: \: \: \: \: \underline{ \boxed{ \purple{ \bold{ \rm{V = \frac{total \: distance}{total \: time} }}}}} \\ \\ \star \rm \: \red{Calculation} \\ \\ \leadsto \rm \: V = \frac{2d}{t} = \frac{2 \times 3750}{5} \\ \\ \therefore \: \boxed{ \bold{ \sf{ \orange{V{ \tiny{signal}} = 1500 \: \frac{m}{s} }}}} \\ \\ \star \rm \: \red{Diagram} \\ \\ \leadsto \rm \: please \: see \: the \: attached \: image... \\ \\ \star \rm \: \red{Extra \: Information} \\ \\ \implies \rm \: This \: method \: is \: used \: for \: find \\ \rm \: out \: real \: depth \: of \: sea. \\ \\ \implies \rm \: At \: other \: side \: it \: is \: also \: useful \\ \rm \: to \: find \: out \: enemy \: ships.$