A ship travelling towards the shore is away from the shore by 121 miles. A plane is travelling from shore at 10 times speed of the ship towards the ship. How long from the shore will they meet?
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Step-by-step explanation:
Let the speed of the ship be 1 mile/h and then speed of the plane becomes 10 miles/h.
Let time t is taken to cover the distance x from point B to point C by ship.
Hence, in time t plane will cover (18 + x) miles.
Now,
x1=18+x10
Or, 10x = 18 + x
Or, x = 2 miles.
Hence, ship will cover 2 miles in 2 hours and plane will cover 20 miles in same time.
Short method:
Relative speed = (10 - 1) = 9 miles/h.
hence, time taken to catch up the ship is 2 hours so distance covered by the ship = 20 miles.
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