Math, asked by matingathani, 1 year ago

A ship whose mass is 5x107kg is initially at rest is pulled by a force of 15x104N through a distance of 10m. If the resistance due to water is negligible then what is the speed of the ship.

Answers

Answered by Anonymous
1
F=ma
a= (15×104)÷(5×107)
a= 2.91 m/s^2
v^2=2as
V^2= 2×2.91×10
v= 7.6 m/s
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