Question

A shipwreck salvage company uses a lifting bag to raise a cannon off the sea bed. The bag is inflated with nitrogen to a volume of 5 m³ at the sea bed pressure of 300 kPa. Assuming no change in temperature, what would the volume of the lifting bag be at sea level where the pressure is 100 kPa?

Answer 1

Answer:

15m³ is your answer

Explanation:

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Answer 2

Answer:

The volume of the lifting bag at sea level, V₂ = $15m^{3}$.

Explanation:

Given,

The volume of nitrogen at the sea bed, V₁ = $5m^{3}$

The pressure at the sea bed, P₁ = $300kPa$

The pressure of the lifting bag at sea level, P₂ = $100kPa$

The volume of the lifting bag at sea level, V₂ =?

The temperature is constant.

Now, as we know,

• According to Boyle's law, at a constant temperature, the pressure is inversely proportional to the volume of the gas.
• P $\alpha \frac{1}{V}$
• PV = constant
• $P_{1} V_{1} = P_{2} V_{2}$

After putting the given values of pressure and volume in the equation, we get:

• $300\times 5 = 100\times V_{2}$
• V₂ = $15m^{3}$

Hence, the volume of the lifting bag at sea level, V₂ = $15m^{3}$.