Question

A SHM is represented by d2x/dt2+ax = 0 . what is its time period

Answer 1

d²x/dt²= –ax
comparing it with , d²x/dt²= –w²x we get w²=a , i.e. w=√a
and T=2π/w = 2π/√a
hope it helped !

Answer 2

Answer:

d²x/dt²= -ax

d²x/dt²= -w²x

w²=k

w=root k

T=2 pi/w

T=2 pi/ root k