Question

a shm of amplitude .01m has a time period of 2s calculate velocity and acceleration when displacement is of half of amplitude​

Answer 1

Answer:

Let equation of SHM is x=Asin(ωt), Where A=0.2 m,

∴v=Aωcos(ωt),

∴ Velocity at mean position v=Aω

Given, Time Period=0.01=

ω

2π

⇒ω=200π

∴ Velocity=0.2×200π=40π