A shoe box has a length of 10 cm, a width
of 8 cm, and height of 12 cm. Find the total
surface area of the shoe box. If the top of the
shoe box is torn off, what will be the surface
area of the remaining box?
Answers
Answered by
3
Answer:
l = 10cm
b = 8cm
h = 12cm
T.S.A
= 2(lb+bh+hl)
= 2(10×8 + 8×12 + 12×10)
= 2(80+96+120)
= 2(296)
= 592 cm^2
Remaining surface area
= 2h(l+b) + l×b
= 2×12(10+8) + 10×8
= 24(18) + 80
= 432 + 80
= 512cm^2
Answered by
1
Step-by-step explanation:
Given: length = 10 cm
width = 8 cm
height = 12cm
Total surface area = 2( l×b + b×h + h×l )
= 2 ( 10×8 + 8×12 + 12×10 )
= 2 ( 80 + 96 + 120 )
= 2 × 296
= 592 cm square unit
Surface area of remaining box = total surface area - area of top of the shoe box
= 592 cm. sq unit - l×b
= 592 cm. sq unit - (10×8) cm sq unit
= 592 cm. sq unit - 80 cm sq unit
= 512 592 cm. sq unit
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