Math, asked by sharansk, 10 days ago

a shoemaker incurs an expense of rs 200 for producing a shoe she also incurs an additional expenditure of rs. 50,000 independent of the number of shoes produced. if she can sell a shoe during the season . she sells for rs. 300 else, she sells each shoe for rs. 150 if she produces 2000 shoes. Determine the number of shoe that she much sell during the season to breakeven.​

Answers

Answered by amitnrw
3

Given : A shoemaker incurs an expense of Rs 200 for producing a shoe

she also incurs an additional expenditure of Rs. 50,000 independent of the number of shoes produced.

She can sell a shoe during the season . she sells for Rs. 300 else, she sells each shoe for rs. 150

She produces 2000 shoes.

To Find : the number of shoe that she much sell during the season to breakeven.​

Solution:

At breakeven

Total Cost / Expenses  = Total Revenue

Total Cost = Fixed Cost + Variable cost

Fixed cost = Rs 50000

Variable cost = 2000 * 200  = 400000  Rs

Total Cost = 450000  Rs

Let say x  Numbers sold during the season

=> 2000 -x   sold else

Revenue During season = 300x  Rs

Else Revenue   = 150(2000 - x)  = 300000 - 150x  Rs

Total Revenue = 300x + 300000 - 150x  

= 300000 + 150x     Rs

Equate Total Cost and Total Revenue

300000 + 150x   =  450000

=> 150x   =150000

=> x = 1000

Hence 1000 to be sold during the season for breakeven

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Answered by sourasghotekar123
0

Answer:

He needs to sell 1000 shoes during seasion to meet the breakeven point.

Step-by-step explanation:

As per the data given in the question,

We have,

Expense on each shoe = Rs 200

Additional expenditure = Rs 50000

Cost of each shoe in season = Rs 300

Cost of each shoe off season = Rs 150

Total shoe produced = 2000

Now,

Let x shoes were sold in season.

So, shoes sold in offseason will be (2000-x)

Since, we need to match the break even. The equation will be

300x+150(2000-x)=2000\times200+50000\\150x=450000-300000\\150x=150000\\x=1000

Hence, he needs to sell 1000 shoes during seasion to meet the breakeven point.

#SPJ2

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