Question

A shooter can hit a target in 3 out of 5 shots and another shooter can hit the target in 2 out of 4 shots. Find the probability that the target is being hit (a) when both of them try (b) by only one shooter.

Answer 1

Step-by-step explanation:

Let the first shooter be A and the second shooter be B.

The probability that A shoots and hits the target Is = 3/5

The probability that B shoots and hits the target is = 2/4

We can then calculate the following probabilities :

1) The probability that both shoot and hit the target.

This is written as :

P(A shoots and hits the target) and P(B shoots and hits the target)

= 3/5 × 2/4 = 6/20 = 3/10

2) Probability that the target is being hit by only one shooter.

P(A hits the target) or P(B hits the target)

Let the total shots be 5 + 4 = 9

3/9 for A.

2/9 for B

3/9 + 2/9 = 5/9