Question

A shop keeper bought two projectors for Rs 50,000. He sold one at a profit of 5% and other at a loss of 5%. If the selling price of each projector is same, determine the CP of each projector.​

Answer 1

Answer:

it is simple

CP¹ = 50000×5/100 =2500

SO CP = 52500Rs

CP² = 50000-2500 = 47500

Step-by-step explanation:

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Answer 2

Given: A shop keeper bought two projectors for Rs 50,000. He sold one at a profit of 5% and other at a loss of 5%. The selling price of each projector is the same.

To find: The C.P. of each projector.​

Solution:

• Let the cost of one projector be x and the other projector be (50000 - x).
• So, the cost of one of the projector can be calculated as,

        $S.P. = C.P. + \frac{5}{100} * C.P.$

• Here, S.P. is the selling price, C.P. is the cost price, 5/100 indicates the 5% and the plus sign indicates profit.

        $S.P. = x + \frac{5}{100} * x$

        $S.P. = \frac{105}{100} x$

• So, the cost of the other projector can be calculated as,

        $S.P. = C.P. - \frac{5}{100} * C.P.$

• Here, the minus sign indicates loss.

        $S.P. = (50000-x) - \frac{5}{100} * (50000-x)$

        $S.P. = 47500 - \frac{95}{100} x$

• Since the selling price of each projector is the same, they must be equated as follows,

        $\frac{105}{100} x = 47500 - \frac{95}{100} x$

        $x = 23750$

• So, the value of x is 23750 and the value of (50000-x) is 26250.

Therefore, the C.P. (cost price) of one projector is Rs.23750 and of the other projector is Rs. 26250.