Math, asked by rutikshagaonkar5613, 11 months ago

A shop keeper has 2 types of rice out of them one is 70 rs and another one is 40 rs he is mixing them in a ration of 7:3. At what cost he should sell kg rice to get 20 percent profit

Answers

Answered by singhprasannjeet7
0

Answer:

He should sell for 73.2 rupees per/kg

Step-by-step explanation:

Let the ratio be 7x and 3x

And let the sum of their weight be 1000 g(1 kg)

7x+3x=1000

10x=1000

x=1000/10=100 g

weight of 1st rice in mixture= 7x= 700 g

weight of 2nd rice in mixture= 3x= 300 g

Let the prices of both the rice be for 1000 g(1 kg).

So,

Cost of 1st rice for 1000 g=70

Cost of 1st rice for 1 g=70/1000

Cost of 1st rice for 700 g= 70/1000*700 =49

Cost of 2nd rice for 1000 g=40

Cost of 2nd rice for 1 g=40/1000

Cost of 2nd rice for 300 g= 40/1000*300 =12

Total Cost of 1000 g of mixture= 49+12 =61

Profit=61*20/100 =12.2

SP = 61+12.2=73.2

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