Question

A shop keeper reduced the price of sugar by 10%. A person can buy 2 kg more sugar for

Rs.900. The difference between the original price and the reduced price, per kg, is

(in rupees)
​

Answer 1

A reduction of 10% in the price of sugar enables a housewife to buy 6.2kg more for Rs. 279. What is the reduced price per kg?

Method 1

6.2kgs is 279 rupees

1kg is 279/6.2 rupees

10% of 279/6.2 =4.5 rupees

Method 2

279/x -279/90% of x = 6.2

x=31/6.2

90%of 31/6.2 is 4.5 rupees

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If A x B = Constant, then a reduction of 1/x th part in A will result in increase of 1/(x - 1) th part in B.

=> Reduction in A by 10% = 1/10 th will lead to increase of 1/9 th in B.

=> If original quantity purchased is q, then :

1/9q = 6.20 kgs

=> q = 55.80 kgs

=> Original price of bananas = 279/55.80 = Rs 5/kg

New quantity = 55.80 + 6.20 = 62

New Reduced price = 279/62 = Rs 4.50 /kg

:-

Answer 2

Answer:

Difference Between Original Price and Reduced Price is Rs. 5

Step-by-step explanation:

Let the original Price of sugar be x

the original Quantity of sugar be y

According to the question,

xy = 900

$(x-\frac{10}{100}x)(y+2)=900$

$xy-\frac{10}{100}xy+2x-\frac{10\times2}{100}x=900$

$900-\frac{1}{10}\times900+2x-\frac{1}{5}x=900$

$-90+\frac{9x}{5}=0$

9x/5 = 90

x = 10 × 5

x = 50

Reduced Price of Sugar = 50 - 10/100 × 50 = Rs. 45

Difference Between Original Price and Reduced Price = 50 - 45 = Rs. 5

Therefore, Difference Between Original Price and Reduced Price is Rs. 5