A shop keeper sells a article A at 8% profit and article B at 10% loss there by getting a sum of rs.1008. If sells the article A at 10% profit and article B at 8% loss he would have get rs.1028 . Find the cost price of both of them article.
Answers
Let the CP of saree and that of sweater be x and y respectively.
Case 1.
Given that saree is sold at 8% profit
=> SP of saree = x + 8x/100 = 108x/100
Also, sweater is sold at 10% discount
=> SP of sweater = y - 10y/100 = 9y/10
Given that saree and sweater fetch Rs 1008,
108x/100 + 9y/10 = 1008
=> 108x+90y/100 = 1008
=> 108x + 90y = 100800 => 6x + 5y = 5600 => x = 5600-5y/6 (i)
Case 2.
Given that saree is sold at 10% profit
SP of saree = x + 10x/00 = 11x/10
Also, sweater is sold at 8% discount
=> SP of sweater = y - 8y/100 = 92y/100 =
Given that saree and sweater fetch Rs 1028,
11x/10 + 92y/100 = 1028
=> 110x+92y/100 = 1028
=> 110x+92y = 102800
Putting value of (i)
110 (5600-5y/6) + 92y = 102800
=> 616000-550y/6 + 92y = 102800
=> 616000-550y-552y/6 = 102800
=> 616000+2y/6 = 102800
=> 616000+2y = 616800
=> 2y = 800
=> y = Rs400
From (i),
x = 5600 - 5*400/6
x = 5600-1200/6
x = 4200/6
=> x = Rs700
Therefore, SP of saree = Rs700
List price of sweater = Rs 400