Question

a shop keeper sells two bikes for 72000. for first bike he gains 20% for second bike he losses 20% whether he gets profit or loss

Answer 1

sp=72000
cp of 1 St bike
sp= cp*(1-p%)
cp= 60000

similary cp of 2nd bike
cp= 90000
net profit= 6000

Answer 2

SP of two bikes = 72000
P% of 1st bike = 20%
CP of 1st bike = [sp×100/100+p%]
= [72000×100/100+20]
= [72000×100/120]
= 60,000
L% of 2nd bike = 20%
CP of 2nd bike = [sp×100/100-L%]
= [72000×100/100-20]
= [72000×100/80]
= 90,000
Total SP of both bikes = (72000+72000)
= Rs.1,44,000
Total CP of both bikes = (60000+90000)
= Rs.1,50,000
As the CP is greater than SP, the shopkeeper gets loss.
Loss = CP-SP
= (150000-144000)
= Rs.6000
Loss Percentage = [L/CP×100%)
= [6000/150000×100%]
= 0.04× 100%
= 4%
hope it helps and pls mark it as brainliest answer