A shop owner blends three type of tea.A,B,C, in the ratio 6:4:7.if the mass of tea C in the mixture is 28kg find the difference in the masses of the other two types of tea.
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Solution:-
The ratio of three types of tea = 6:4:7
Sum of the ratio = 6+4+7 = 17
Mass of tea 'C' in the mixture = 28 kg
Total mass of tea in the mixture = (17 × 28)/7
⇒ 476/7 = 68 Kg (Total mass of all three types of tea)
Mass of 'A' = (6 × 68)/17 = 24 Kg
Mass of 'B' = (4 × 68)/17 = 16 Kg
Difference between Type 'A' and type 'B' tea = 24 - 16 = 8 Kg
Answer.
The ratio of three types of tea = 6:4:7
Sum of the ratio = 6+4+7 = 17
Mass of tea 'C' in the mixture = 28 kg
Total mass of tea in the mixture = (17 × 28)/7
⇒ 476/7 = 68 Kg (Total mass of all three types of tea)
Mass of 'A' = (6 × 68)/17 = 24 Kg
Mass of 'B' = (4 × 68)/17 = 16 Kg
Difference between Type 'A' and type 'B' tea = 24 - 16 = 8 Kg
Answer.
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