Math, asked by shivamarora1823, 1 year ago

A shop owner has a sale of Rs 7535, Rs. 8056, Rs.
7854, Rs. 7230 and Rs. 8562 for 5 consecutive
months. How much sale must he have in the sixth
month so that he gets an average sale of Rs. 7500?
a) 5991 b) 5467 c) 5987 d) 6453 e) 5763

Answers

Answered by Anonymous
34
Solutions :-


Given :

Sale of first month = Rs 7535
Sale of second month = Rs 8056
Sale of third month = Rs 7854
Sale of fourth month = Rs 7230
Sale of fifth month = Rs 8562

Let the sale of sixth month be x

Average sale = Rs 7500


A/q
 =  >  \frac{7535 + 8056 + 7854 + 7230 + 8562 + x}{6}  = 7500 \\  \\  =  >  7535 + 8056 + 7854 + 7230 + 8562 + x = 7500 \times 6 \\  \\  =  > 39237 + x = 45000 \\  \\   = > x =  45000 - 39237 = 5763


Hence,
e) Rs 5763 is the required answer.

Anonymous: thanks :)
Answered by ans81
37
HEY MATE HERE IS YOUR ANSWER

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Given :-

A shop owner sale 5 months :-

Sale of 1st month :- ₹ 7535

Sale of 2nd month :- ₹ 8056

Sale of 3rd month :- ₹ 7854

Sale of 4th month :- ₹ 7230

Sale of 5th month :- ₹ 8562

Let the 6th sale be x.

Average sale = ₹ 7500

ATQ,

= > \frac{7535 + 8056 + 7854 + 7230 + 8562 + x}{6} = 7500

 = > 39237 + x = 7500 \times 6

➡️ 39237 + x = 45000

➡️ x = 45000 - 39237

➡️ x = 5763

Therefore,

OPTION E, is correct

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Ansh as ans81
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