A shop sells AC machines at the rate of 2.5 pieces per week,
find the probability that in a 2-week period the shop sells at least 7 AC
machines
Answers
Answer:
0.015.
Explanation:
The average rate is lambda = 2 errors per page.
We don't have an exact probability (e.g., "there is a 50% chance that a page contains errors").
As a result, Poisson distribution.
(2 errors per page * 1 page) = (lambda t)
Hence P0 = 2^0/0! * exp(-2) = 0.135.
Again, an average rate is provided: lambda = 0.5 crashes per day. As a result, Poisson.
P2 = (3.5)2/2! * exp (-3.5) = 0.185 for (lambda t) = (0.5 per day * 7 days) = 3.5/week and n = 2.
We have a chance of something being true and something else not being true; in this case, an ic is faulty. Thus, the Binomial distribution.
p = Probability of faulty = 0.02, q = Probability of not faulty = 0.98, n = 10. (q + p)10 is multiplied by 10 to get
q^10 + 10 q^9 p + 10(10-1)/2! q^8 p^2 + ...
0 1 2 Number of faulty integrated circuits
So, the possibility of a box containing two faulty ics
P2 = 10(10-1)/2! q^8 p^2 = 0.015.
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