A shop sold 2 identical digital cameras and 5 identical CD players on a praticular day. The price of 3 such digital cameras and 6 such CD players was $460 more. If a digital camera cost $80 more than a CD player, find the cost of each digital camera.
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Answer:
DC - Digital cams
CD - CD players
2DC+5CD+$460=3DC+6CD
3DC+6CD-2DC-5CD=$460
DC+CD=$460
DC=CD+$80
CD+$80+CD=$460
2CD=$460-$80=$380
CD=$190
DC=$190+$80=$270
Cost of each digital cam = $270
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