Question

A shopkeeper allows a discount of 10% on the marked price of an item but charges a sales tax of 8% on the discount price. If the customer pays ₹680.40 as the price including the sales tax, then what is the marked price of the item? Please give full solution.

Answer 1

Let MP = x
Price after discount of 10% = x - (x*10/100) = 9x/10
Price after tax = 9x/10 + ( 9x/10 * 8/100 ) = 972x/1000

972x/1000= 680.40
X= 700 answer

Answer 2

Marked price of a item is Rupees 700

Given:

A shopkeeper allows 10% discount on the market price.

To Find:  

Marked price of item

Solution:

Let marked price of item = x

10% discount on marked price $=x-(10 \% \text { of } x)=x-\left(\frac{10}{100} \times x\right)=\frac{9 x}{10}$

Hence the discounted price $=\frac{9 x}{10}$

Given 8 % of sales tax on the discount price $=\left(\frac{8}{100} \times \frac{9 x}{10}\right)+\frac{9 x}{10}=\frac{72 x}{1000}+\frac{9 x}{10}=\frac{972 x}{1000}=\frac{243 x}{250}$

The price paid by the customer = Rs. 680.40

$\begin{array}{l}{\frac{243 x}{250}=680.40} \\\\ {x=\frac{680.40 \times 250}{243}=700}\end{array}$