A shopkeeper blended some quantity of tea
bought at 49 per kg with double amount
of another kind of tea bought at 48 per
kg. He made a profit of 10% by selling the
total quantity of the blended tea at 1595.
What was the quantity of tea bought by
the shopkeeper all together?
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Answer:
30 kg of sugar
Step-by-step explanation:
Let, he bought x kg of sugar at 49/kg
Therefore, he bought 2x kg of sugar at 48/kg
Total cost for (x+2x) = 3x kg of sugar bought is
= x kg*49/kg + 2x kg*48/kg = 145x
At 10% profit, selling price of this 3x kg sugar will be = 145x*(1+10%) = 159.5x
According to question, 159.5x = 1595
or x = 10 or 3x = 30
Therefore, he bought 30 kg of sugar.
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