Math, asked by XxbadgirlxX01, 3 months ago

A shopkeeper blends two types of rice, one costing ₹12.50 / kg and the other costing ₹14 / kg in the ratio of 4: 5. Find his profit percent if he sells the mixture at ₹16 / kg.​

Answers

Answered by ItzMissLegend
7

LCM of 4 and 5 =20

cost of first rice =12.50× 20

=₹250

cost of second rice =14×20

=₹280

Total cp =250+280=530

Total sp =16×20 =₹320

Profit =530-320=₹210

Profit%=210×100÷320 = 65.6% Ans.

Answered by MrImpeccable
11

ANSWER:

Given:

  • Cost of two types of rice = ₹12.50 / kg & ₹14 / kg
  • Ratio of the two types in mixture = 4 : 5
  • Cost Price of Mixture = ₹16 / kg.

To Find:

  • Profit Percent

Solution:

We are given that,

⇒ Ratio of the two types of rice in the mixture = 4 : 5

So,

Let the quantity of each type of rice be 4x and 5x respectively.

Hence,

⇒ Quantity of ₹12.50 / kg rice = 4x

⇒ Quantity of ₹14 / kg rice = 5x

Now,

⇒ Total Cost of 1st type of rice in mixture = 12.50 × 4x

⇒ Total Cost of 1st type of rice in mixture = ₹50x

And,

⇒ Total Cost of 2nd type of rice in mixture = 14 × 5x

⇒ Total Cost of 2nd type of rice in mixture = ₹70x

Hence,

⇒ Original cost of mixture of price = ₹50x + ₹70x

⇒ Original cost of mixture of price = ₹120x -------(1)

(This is our Cost Price.)

We are given that,

⇒ Cost of mixture per kg = ₹16.

And,

⇒ Total quantity of rice used per kg in the mixture = 4x + 5x = 9x.

Hence

⇒ Final total cost of mixture of rice = 16 × 9x

⇒ Final total cost of mixture of rice = ₹144x -------(2)

(This is our Selling Price.)

We know that,

Profit % = (SP - CP)/CP × 100

So,

⇒ Profit % = (144x - 120x)/120x × 100

⇒ Profit % = 24x/120x × 100

⇒ Profit % = 1/5 × 100

⇒ Profit % = 0.2 × 10

⇒ Profit % = 20%

Therefore, the profit % is 20%.

Formula Used:

  • Profit % = (SP - CP)/CP × 100
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