Math, asked by sujatadpatil83, 2 months ago

A shopkeeper borrow RS.9,500 from his friend at 8% p.a and repay RS.11,020. After how many years did he repay.

Answers

Answered by Anonymous
8

Answer:

hi

SI =P×R×T/100

T =SI×100/P×R

SI =Amount -Principal

SI =11020-9500

SI = 1520

T =1520 ×100/9500×8

T =152000/76000

T = 2

So he repaid the money after 2 years.

Answered by mahasamymahasamy
1

Step-by-step explanation:

Shopkeeper bought =9500

after y no of years he returned = 11020

he bought at the interest of 8%

for 1 year the value of interest is

x = 9500/100 * 8

x =95*8

x =760

we found 1 year of interest

11020. =9500+760x

11020-9500. =760x

760x. =1520

x. =1520/760

x=2

The shopkeeper returned amount after two years

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