A shopkeeper bought 200 articles costing the same if we sold 30% of the article at 20% loss and remaining at 10% profit if the total profit made by him is rupees 220 find the CP of an article
Answers
Answer:
The CP of one article is Rs.110
Step-by-step explanation:
Total number of articles = 200
Let the CP of each article = "x"
Part 1
30% articles were sold at 20% loss
30% of 200 = 0.3*200 = 60
=> 60 articles were sold at 20% loss
CP of 60 articles = 60x
There was a loss of 20% in the transaction. This means:
SP = CP - (20% of CP)
SP = CP - 0.2*CP
SP = 0.8*CP
Now, CP = 60x
=> SP = 0.8*60x
=> SP = 48x
Part 2
70% articles were sold at 10% profit
70% of 200 = 0.7*200 = 140
=> 140 articles were sold at 10% profit
CP of 140 articles = 140x
There was a profit of 10% in the transaction. This means:
SP = CP + (10% of CP)
SP = CP + 0.1*CP
SP = 1.1*CP
Now, CP = 140x
=> SP = 1.1*140x
=> SP = 154x
For overall transaction of 200 articles
CP = 200x
SP = 48x + 154x
SP = 202x
Profit = SP - CP
= 202x - 200x
= 2x
ATQ, total profit = Rs.220
=> 2x = 220
=> x = 110
The cost per article is Rs.110
Verify:
Total number of articles = 200
CP for 1 article = Rs.110 => Total CP = Rs.22,000
30% of articles sold at 20% loss
=> 60 articles sold at Rs.88 each
=> SP for 60 articles = Rs.5280
70% of articles sold at 10% profit
=> 140 articles sold at Rs.121 each
=> SP for 140 articles = Rs.16940
Total SP = Rs.(5280 + 16940) = Rs.22,220
Total CP = Rs.22,000
Total Profit = Total SP - Total CP
= 22220 - 22000
= 220
Total profit = Rs.220 (as given, thus verified)