a shopkeeper bought 200 water bottles.He sold four-fifth of them at 15% profit and the rest at 10% profit.find the cost price of the water bottles if he earns a profit of rs 238
Answers
Answer:
Rs 1700
Step-by-step explanation:
Let the cost price of the water bottle be x for each water bottle.
The bottles sold at a gain of 15% = 4/5 × 200 = 160
The cost price = 160x
Profit = 0.15 × 160x = 24x
The ones sold at a profit of 10% = 200 - 160 = 40
The cost price = 40x
The profit = 0.10 × 40x = 4x
The total profit will be given by :
24x + 4x = 238
We now need to solve for x.
28x = 238
x = 238/28
x = Rs 8.5
This is the cost price of each water bottle.
The cost price of the 200 water bottles will be = 200 × 8.5 = Rs 1700
Answer:
Rs 8.5 per Bottle
Rs 1700 for 200 Bottles
Step-by-step explanation:
a shopkeeper bought 200 water bottles.He sold four-fifth of them at 15% profit and the rest at 10% profit.find the cost price of the water bottles if he earns a profit of rs 238
Let say cost Price of Bottle = Rs B
Cost Price of 200 Bottles = Rs 200B
Selling Price per bottle of 4/5 Bottles = B + (15/100)B = Rs 1.15B
4/5 Bottles = 4 * 200/5 = 160
Selling Price of 160 Bottles = 160 * 1.15 B = Rs 184B
Rest Bottles = 200 - 160 = 40 Bottles
Selling Price per bottle of rest bottles = B + (10/100)B = Rs 1.1B
Selling price of 40 Bottles = 40 * 1.1B = Rs 44B
Selling Price of 200 Bottles = 184B + 44B = 228B
Profit = 228B - 220B = Rs 28B
28B = 238
=> B = 8.5
Cost Price of water bottle = Rs 8.5
200 Bottles price = 200B = 200 * 8.5 = Rs 1700