A shopkeeper bought 3 tables at Rs.250 each.He sold the first one at a profit of 20%,the second one at a loss of 16% and the third one was sold at such a price that his total profit was 15%.what was the selling price of the third table?
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Answers
Given :-
The cost price of each table = Rs.250
Profit on 1st table by selling = 20%
Loss on 2nd table by selling = 16%
Profit on whole calculation = 15%
To Find :-
The selling price of 3rd table = ?
Solution :-
To calculate the selling price of 3rd table at, first we have to find out total cost price and selling price then setting up equation by applying formula. Before calculation , we have to assume the selling price of 3rd table P.
Calculation for 1st table :-
[Cost price = Rs.250. Profit = 20%]
⇒ SP = (100 + P%)/100 × CP
⇒ SP = (100 + 20)/100 × 250
⇒ SP = 120/100 × 250
⇒ SP = 12 × 25
⇒ SP = Rs.300
Calculation for 2nd table :-
[Cost price = Rs. 250. Loss = 16%]
⇒ SP = (100 - L%)/100 × CP
⇒ SP = (100 - 16)/100 × 250
⇒ SP = 84/100 × 250
⇒ SP = 21 × 10
⇒ SP = Rs.210
Calculation for 3rd table :-
[Cost price = Rs. 250. Selling price = P]
Calculation for total CP and SP :-
⇒ Total CP = Cost of 3 tables
⇒ Total CP = 250 × 3
⇒ Total CP = Rs. 750
⇒ Total SP = Selling of 3 tables
⇒ Total SP = SP(1st + 2nd + 3rd) tables
⇒ Total SP = 300 + 210 + P
⇒ Total SP = Rs.(510 + P)
By solving above we have here :-
[Total CP = Rs.750. Total SP = Rs. (510 + P). P = 15%]
⇒ SP = (100 + P%)/100 × CP
⇒ 510 + P = 115/100 × 750
⇒ 510 + P = 1.15 × 750
⇒ 510 + P = 862.5
⇒ P = 862.5 - 510
⇒ P = Rs. 352.5
Hence, the selling price of 3rd table (P) = Rs. 352.5 :-✅
Cost price of a T.V set =Rs 10000
profit =10%
Selling price =[100+p/100]×C.P
=[100+10/100]×10000
=110/100×10000
=11×1000
=Rs. 11000
Loss =10%
Selling price =[100−L/100]×C.P
=100−10/100×10000
=90/100×10000
=9×1000
=9000
Total cost price =10000+10000 =20000
Total selling price =11000+9000=20000
Here C.P=S.P
Therefore, it is neither Loss nor Profit.