Question

A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% of bananas were rotten. Find the percentage of fruits in good condition.​

Answer 1

Answer:

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Step-by-step explanation:

Total number of fruits shopkeeper bought = 600 + 400 = 1000

Number of rotten oranges = 15% of 600

= 15/100 × 600

= 9000/100

= 90

Number of rotten bananas = 8% of 400

= 8/100 × 400

= 3200/100

= 32

Therefore, total number of rotten fruits = 90 + 32 = 122

Therefore Number of fruits in good condition = 1000 - 122 = 878

Therefore Percentage of fruits in good condition = (878/1000 × 100)%

= (87800/1000)%

= 87.8%

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Answer 2

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Total no. of fruits shopkeeper bought ➡

600 + 400 = 1000

♠No. of rotten oranges = 15% of 600

$\implies\frac{15}{100}*600$

$\implies\frac{9000}{100} \\ \\ \implies\ 90$

♠No. of rotten bananas = 8% of 400

$\implies\frac{8}{100}*400$

$\implies\frac{3200}{100} \\ \\ \implies\ 32$

♠No. of total rotten fruits [Orange + Banana]=90+32= 122

♠Fruits in good condition = 1000-122=

878..

♠% of fruits in good condition ➡

$\implies\frac{878}{1000}$

$\implies\frac{87800}{1000} \\ \\ \implies\ 87.8$

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