Question

A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% of bananas were rotten. Find the percentage of fruits in good condition.


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Answer 1

Answer:

He found 15% of orange and 8% of bananas rotten. What is the percentage of fruits in good condition? Total fruits = 600 + 400 = 1000. Out of this 15% oranges = 15/100 * 600 = 90 and 8% bananas = 8/100 *400 = 32 bananas are spoiled.

Answer 2

Answer :-

total number of fruits shopkeeper bought = 600 + 400 = 1000

Number of rotten oranges =

= 15 % of 600

$\dashrightarrow\sf \: \frac{15}{100} \times 600$

$\dashrightarrow\sf \: \cancel\dfrac { 9000 } { 100} = 90$

$\dashrightarrow\sf \: 90$

number of rotten bananas =

= 8 % of 400

$\dashrightarrow\sf \: \frac{8}{100} \times 400$

$\dashrightarrow\sf \: \cancel\dfrac { 3200 } { 100 } = 32$

$\dashrightarrow\sf \: 32$

hence total number of rotten fruits = 90 + 32 = 122

therefore number of fruits in good condition = 1000 - 122 = 878

therefore percentage of fruits in good condition =

$\dashrightarrow\sf \: ( \frac{878}{1000} \times 100)$

$\dashrightarrow\sf \: \cancel\dfrac { 87800 } { 1000} = 87.8$

$\dashrightarrow\sf \: 87.8$

so therefore our required answer is 87.8